The mass of 1.00 L ( = 1000 mL) of water is: m = × = × =ρ V 0.997 1000 997g The molar mass of H 2O is: 2 ×××× 1.01 (H) + 16.00 (O)=18.02 g mol-1 Hence, the number of moles in 997 g is: mass(m) 997 numberof moles(n) 55.3mol molarmass(M) 18.02 = = =
A 1.547-g sample of blue copper(II) sulfate pentahydrate, CuSO4∙5H2O, is heated carefully to drive off the water. The white crystals of CuSO4 that are left behind have a mass of 0.989 g. How many moles of H2O were in the original sample? Show that the relative molar amounts of CuSO4 and H2O agree with the formula of the hydrate. buy: ch216

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How many tons of sea water would have to be processed in order to obtain 1.0 g of gold? 21. A solution contains 5.0 g of sodium hydroxide per liter. How many grams will be contained in 50 ml? 22. A solution contains 40 g of potassium nitrate per liter. How many milliliters of this solution will be needed in order to get 8.0 g of potassium ... How many grams CuSO4.5H2O in 1 mol? The answer is 249.685. We assume you are converting between grams CuSO4.5H2O and mole. You can view more details on each measurement unit: molecular weight of CuSO4.5H2O or mol The SI base unit for amount of substance is the mole. 1 grams CuSO4.5H2O is equal to 0.0040050463584116 mole.

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Calculate the number of grams of C6H6 needed to produce 50.0 g of water. 50.0g H2O/ 1 mol H2O/ 2 mol C6H6/ 78 g C6H6 = 72.2 g C6H6 1 / 18g H2O / 6 mol H2O / 1 mol C6H6 8. Calculate the number of moles of water produced when 75 g of oxygen react. 75g O2/ 1 mol O2/ 6 mol H2O = 0.94 mol H2O 1 / 32g O2 /15 mol O2 H. Cannon, C. Clapper and T ...

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100mL of H 2 O =Amount of Solute needed to saturate Let’s look at an example of this calculation using the curve on pg. 1: • At 10oC, 80 g of NaNO3 will dissolve in 100 mL (a saturated solution) • Say we only needed 60 mL of a NaNO3 solution. 60mL H 2 O × 80g NaNO 3 100 mL H 2 O =48g of NaNO 3 Mar 14, 2013 · How many grams of CuSO4 x 5H2O are needed to make 500.0 mL of a 0.050 M solution?

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1 Answer to Calculate the grams of CuSO4 5H2O whose purity is 99.10% to prepare 250.0 mL of solution 0.100 M. I need procedure and answer.

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Calculate the density of a 3.00 102-g object that has a volume of 50.0 mL. What volume, in liters, will 8.00 102 g of air occupy if the density of air is 1.29 g/L? What is the mass, in grams, of a piece of iron that has a volume of 1.50 102 mL and a density of 7.20 g/mL? What is the mass of a femur (leg bone) having a volume of 118 cm3? 0.45 Molar solution of copper sulphate hexahydrate contains 0.45 moles of in 1 liter. Thus, essentially, we'd be having 0.45*0.8=0.36 moles in 800 ml of the solution. A quick calculation of the molar mass of the CuSO4.6H2O gives us the result as...

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0.45 Molar solution of copper sulphate hexahydrate contains 0.45 moles of in 1 liter. Thus, essentially, we'd be having 0.45*0.8=0.36 moles in 800 ml of the solution. Mar 14, 2013 · How many grams of CuSO4 x 5H2O are needed to make 500.0 mL of a 0.050 M solution? Apr 02, 2020 · The chemical reaction between hydrochloric acid and magnesium produces magnesium chloride and hydrogen gas. The balanced chemical equation for this reaction is Mg (s) + 2 HCl (aq) produces MgCl 2 (aq) + H 2 (g), where the letter "s" stands for solid, "g" is gas and "aq" represents an aqueous solution.

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With the aid of heat, dissolve 173g of sodium citrate and 100g of Na2CO3 in 800ml of water. Filter, if necessary, and dilute to 850 ml. Dissolve 17.3 gof CuSO4.5H2O in 100ml of water. Pour the latter solution, with constant stirring, into the carbonate-citrate solution, and make up to 1 liter. Very small quantities of the solutions are used. If you prepare about 1000 mL of each solution, and distribute each in small plastic bottles, the solutions can be kept from year to year and simply replenished as needed. 2. Concentration of all solutions are 0.2 M. Directions for the preparation of the solutions are as follows:

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